256+b^2=1150

Solution for 256+b^2=1150 equation:

256+b^2=1150

We move all terms to the left:

256+b^2-(1150)=0

We add all the numbers together, and all the variables

b^2-894=0

a = 1; b = 0; c = -894;
Δ = b2-4ac
Δ = 02-4·1·(-894)
Δ = 3576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3576}=\sqrt{4*894}=\sqrt{4}*\sqrt{894}=2\sqrt{894}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{894}}{2*1}=\frac{0-2\sqrt{894}}{2}
=-\frac{2\sqrt{894}}{2}
=-\sqrt{894}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{894}}{2*1}=\frac{0+2\sqrt{894}}{2}
=\frac{2\sqrt{894}}{2}
=\sqrt{894}
$